scratch that last statement... but yeah the velocity should be max when it first comes into contact with the spring I am not sure how that isn't correct.
Yeah, acceleration would be gsin30 when the box is traveling down the slope. The acceleration the box experiences when the spring slows it to rest is not zero. So the max velocity of the box is before it hits the spring. There is a slight difference between speed and velocity though perhaps...
I think I agree with your first guess. Also in that problem there is no instant in time at which acceleration is zero since the box would never remain at a constant velocity.
Ok this problem is interesting. For starters the units they ask for are N.s so Newton*seconds. a Newton is 1kg*m/s^2. So 1Kg*m/s^2 *s=1Kg*m/s which is the correct unit for momentum. So there is nothing wrong with saying a momentum is the same thing as a Newton second. (If you want me to explain...
Hello, Yea you need that velocity! I am uncertain if this is right since the title "tricky" makes me feel like I am wrong anyway i think what the issue at hand is...is that you have KEi as zero. Which is not true. The satellite first needed to leave the Earth's gravitational pull. So you have to...
Hello, Well you understand that Work=Force*distance. well let's look at this problem in this way, If a force is applied to an object, and that object slides in the direction of the displacement then the work is positive. so the first one should be W=63 Joules downward. because 21N*3m. Since the...
Well, yes let's assume you want to lift an object with just a pulley. The initial lifting of the object as you stated would need more than the objects gravitational force. Then to have the object lift at a constant velocity the force would just need to be equivalent to the gravitational force...
I would approach the problem using energy as well. Since there is frictional force then energy conservation must involve work. so Kinetic energy(final)+potential energy(final)+Work=potential energy inital+kinetic energy initial. Where potential initial=mgR and kinetic initial=potential...