Simple Physics Help: Understanding Force in Motion | Refresh Your Memory

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SUMMARY

The discussion centers on the physics of force in motion, specifically regarding lifting a weight with a motor. The initial force required to lift the weight is calculated using the formula F = ma + (additional force to overcome resistance). Once the weight reaches a constant velocity of 2 m/s, the force required to maintain that velocity is equal to the gravitational force acting on the weight, as there is no net acceleration. This understanding aligns with Newton's laws of motion, particularly the concept of inertia.

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skyguy
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need some help to refresh my memory.

was just doing some specification checking... when the motor is to lift a weight...

let say the weight is to be move at 2m/s with 2sec when it start... and stay at 2m/s throughout after that...

the initial force would be F = ma + (Watever force it need to overcome)
where ma = m (dv/dt) ... simple

ok now the question... after it have reach the 2m/s velocity should the force F be
F = (watever force it need to overcome) only ?... coz i don't need any more acceleration and just constant speed
 
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Well, yes let's assume you want to lift an object with just a pulley. The initial lifting of the object as you stated would need more than the objects gravitational force. Then to have the object lift at a constant velocity the force would just need to be equivalent to the gravitational force upward. The mass would then have no acceleration/net force and thanks to the laws of inertia would be able to continue traveling upward at a constant velocity.
 
thanks... u safe me lots of trouble
 

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