Recent content by cortozld

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    Find the square root of: 4+4(sqrt3)i

    Woo hoo! Thanks for the help
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    Find the square root of: 4+4(sqrt3)i

    Homework Statement find the square root of: 4+4(sqrt3)i put the answer in a+bi form Homework Equations finding the nth roots: √(r(cos(theta)+isin(theta)))=√r(cos(theta+2(pi)(k)/(n))+isin(theta+2(pi)(k)/(n) where k=0,1 The Attempt at a Solution first i converted my...
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    Solving a 2m Inclined Plane Problem with Negligible Friction

    So that means i have 2gh=v^2(1+.4). Then divide by (1+.4): 2gh/(1+.4)=v^2 and vinally solve for v. which is v=sqrt(2*9.81*2)/(1+.4) so v=5.3 m/s! Thanks a lot :)
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    Solving a 2m Inclined Plane Problem with Negligible Friction

    From gh=.5v^2+.5(.4)v^2 I multiplied both sides by 2 to get rid of the .5: 2gh=v^2+.4v^2. Then I divided by .4 and added the v^2s together: 2gh/.4=2v^2. Divided both sides by 2 again to get: gh/.4=v^2.
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    Solving a 2m Inclined Plane Problem with Negligible Friction

    Yes, your second statement was correct. As for the problem not being specific it's my teacher not me so talk to him :). As for the answer apparently mine is wrong. So if you have any ideas about something I've missed I'd be glad to hear it
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    Solving a 2m Inclined Plane Problem with Negligible Friction

    Homework Statement A solid ball is at the top of a 2 meter inclined plane. Assuming friction is negligible, what is its linear speed (m/s) as it reaches the bottom? Homework Equations PE=mgh KE=.5mv^2 RKE=.5Iw^2 I of ball=.4mr^2 w=v/r The Attempt at a Solution Pretty much what...
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    Orbital Velocity of Equatorial Satellite at 352,000 km

    so my equation will be T^2 \propto 358370000^3? I am getting a really low answer and according to my teacher it is wrong
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    Orbital Velocity of Equatorial Satellite at 352,000 km

    so kepler's 3rd law is T1^2=R1^3 T2^2 R2^3 so T2 is the period, R1 is radius of earth, and R2 is radius of my orbit? what is T1 then?
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    Orbital Velocity of Equatorial Satellite at 352,000 km

    Homework Statement An Earth's satelite is in equatorial orbit at 352,000 km above earth. What is the orbital velocity (m/s) of the satelite (4 sig figs) Homework Equations g1d1^2=g2d2^2 to find gravity at the height of the satellite The Attempt at a Solution I don't really know...
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    Satelite orbiting earth in a circular path

    that was an accidental typo, my bad. I believe its my teachers website, he's been having lots of problems with it since the year started. So unless anyone has an idea about what I'm doing wrong I'll just have to talk to him on Mon.
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    Satelite orbiting earth in a circular path

    Homework Statement What is the orbiting speed (m/s) of a satelite orbiting Earth in a circular path 1000 km above Earth's surface? (Use 4 sig figs) Homework Equations universal constant of 6.67E-11 r of Earth 6.37E6 m (given by teacher) mass of Earth 6E24 kg (given by teacher)...