Recent content by councilmage

For \phi\phi \rightarrow \phi\phi scattering, I think the scattering amplitude translates into a delta potential between the two mesons. Whether the interaction is attractive or repulsive will depend on the sign of the delta potential which then depends on the coefficient of...

\Box^2e^{iq\cdot x} = \partial_\mu\partial^\mu (e^{iq^\mu x_\mu}) = \partial_\mu ( -iq^\mu e^{iq_\mu x^\mu})= (-iq^\mu)(-iq_\mu) e^{iq\cdot x} = -q^2e^{iq\cdot x} So I'm not sure how you obtained j^{\mu}_{2} = -q^{\mu}e^{iq\cdot x}. I should probably have asked that first. I see here...

Both \Box^2 = \Box are often used to refer to the d'Alembertian which is a second derivative. Hence, what you wrote here: does not really make sense.

Hi Luke, without straying into path integrals and propagators, I think Wikipedia has a nice explanation on how we can get rid of the phase dependence of the parity operator: http://en.wikipedia.org/wiki/Parity_(physics)#Possible_eigenvalues"