Recent content by Crusty

Assuming the interest is paid first and then the principle is paid down each year, then yes the new 9% each year would be all the interest. If the fractions of pennies are kept by the loan giver or left off the equations, then there's nothing left at the end of year 3. 3000 * 1.09 - 1 185.16 =...

Paying once a year, then adding interest on the remainder- ((3000*1.09-1185.16)*1.09-1185.16)*1.09-1185.16 = 0.014004 so there's some left over.

Oh I see Well $3,000 is the principle. 9% of $3000 is interest. Subtract the payment from their sum. Then another 9% on this number for the 2nd year interest, etc.

3 payments/year means that a payment is made each 4 months of 1/3rd the annual payment?

How do you write it piecewise again? For writing as an equation, I came up with this but it only works when the numbers aren't equal a*((a-b)/abs(a-b)+1)/2+b*((b-a)/abs(b-a)+1)/2

What was the method for modifying an equation to avoid dividing by zero? I think it involved adding 1 somewhere, then removing the error that creates later. For example, a / b = c It is possible that one of the values placed in the b variable could be 0. How would the equation be...

Given variables A and B How is the maximum of A and B expressed as an equation? Another way of saying it is how do you express MAXIMUM(A,B) as an equation? Given variables A,B,C MAXIMUM(A,B)=C How do you solve for A?

As one divides by smaller and smaller numbers, the output figure approaches but does not reach infinity, no?

Thank you all for the replies so far. When determining the angle of net force, is it necessary to convert the vectors of ball A and B to horizontal and vertical vectors, add the horizontal and vertical vectors, and then convert the horizontal and vertical vector sums into the vector of net...

^ means to the power of. Is this right? -3x^3(2x^3 +3x-4) = -6x^6 - 9x^4 + 12x^3 (x+1)(x-2) = x^2 + x - 2x -2 = x^2 - x - 2 (4x-2)(-x+3) = -4x^2 + 2x + 12x - 6 = -4x^2 + 14x - 6

you can't divide 3 staws into zero groups. You could divide them into 1 group of 3, or 3 groups of 1, or others if you cut the straws into smaller pieces. No mater how small the pieces there will just be more and more groups.

Can this be simPlified?:smile: A = B - sin(degtorad(C)) * sqrt(abs(sqr(D/2) - sqr(sqrt(sqr(E - F) + sqr(B - G))/2))) A, B, C, D, E, F, G are variables. I don't need to simlify down to a numerical value of a variable just now; I'm just wondering if the equation can be simplified. Other terms...

I thought that speed could change the mass or something. - Hm that's nice and simple. So if I applied 1 foot/second of force upward on B, then I'm applying it at 90 degrees relative to A, so then 1 second later the CM would be 1 foot up, and the angle of the bar would be 45?

A = first ball; B = 2nd ball A_x,A_y= A's x,y B_x,B_y = B's x,y CM = Center of Mass At rest the CM will be x = (A_x+B_x)/2; y = (A_y+B_y)/2 So the CM isn't always in the middle of the bar, as it changes based on the force and direction of each ball? So you're saying that the forces on each...

Is there a lay version of that, particularly of Einstein's part? So I take it that there is some equation that relates inertia to speed (to mass?), and at light speed one of those values becomes infinite, which indicates that faster speeds aren't possible?