Compound Interest: 3 Equal Ann. Repayments, $3,000 Loan, 9% Rate

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A $3,000 loan at a 9% annual interest rate requires three equal annual repayments of $1,185.16. Each year, the interest is calculated on the remaining principal before the repayment is deducted. The calculations show that after the first year, the principal reduces to $2,084.84, then to $1,087.32 after the second year, and finally to zero after the third payment. The discussion clarifies the process of calculating interest and principal payments, confirming that the interest is paid first each year. Overall, the method of repayment and interest calculation is accurately outlined and understood.
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You are about to borrow $3,000 from a bank at an interest rate of 9% compounded annually. You are required to make three equal annual repayments in the amount of $1,185.16 per year, with the first repayment occurring at the end of year one. For each year, show the interest payment and principal payment.

I know how to do compound interest, but I don't get what this three equal annual repayments thing is. Can someone explain how to do this problem? Thanks in advance
 
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3 payments/year means that a payment is made each 4 months of 1/3rd the annual payment?
 
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it's not three payments a year. there's a total of three equal annual payments of $1,185.16. I'm supposed to find out the interest and principal per year
 
Oh I see
Well $3,000 is the principle. 9% of $3000 is interest. Subtract the payment from their sum. Then another 9% on this number for the 2nd year interest, etc.
 
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it says three equal payments of 1185.16 but if you multiply that by 3 you don't get 3000(1.09)^3 = 3885.09 o_O how would you do it annually instead of 3 years?
 
Crusty said:
Oh I see
Well $3,000 is the principle. 9% of $3000 is interest. Subtract the payment from their sum. Then another 9% on this number for the 2nd year interest, etc.

their sum is 1185.16*3?
 
Paying once a year, then adding interest on the remainder-
((3000*1.09-1185.16)*1.09-1185.16)*1.09-1185.16 = 0.014004 so there's some left over.
 
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is there a formula for this? so..
year 1 = 3000*1.09 - 1185.16 = 2084.84, principal = 3000, interest = 270
year 2 = 2084.84*1.09 - 1185.16 = 1087.32, principal = 2084.84, interest = 187.64
year 3 = 1087.32*1.09 - 1185.16 = 0, principal = 1087.32, interest = 97.86

is this correct?
 
Assuming the interest is paid first and then the principle is paid down each year, then yes the new 9% each year would be all the interest.
If the fractions of pennies are kept by the loan giver or left off the equations, then there's nothing left at the end of year 3.

3000 * 1.09 - 1 185.16 = 2 084.84
2084.84 * 1.09 - 1 185.16 = 1087.3156; 1087.3156-.0056 = 1087.31
1087.31 * 1.09 - 1 185.16 = 0.0079; 0.0079-0.0079 = 0
 
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you have been very helpful, thank you crusty!
 
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