Recent content by Ctom101

angular velocity of link AB = velocity A / distance from centre of zero velocity velocity A = 0.1m/s distance from centre of zero velocity (a) = 0.05m 0.1/0.05= 2rad/s velocity B = distance from centre of zero velocity x angular velocity of link AB angular velocity of AB = 2rad/s distance...

It says A has a constant velocity of 0.1m/s, so I think acceleration is 0 Looking over it again I think I worked out the length b incorrectly. link AB = 0.2m Height = 0.05m Pythagoras: a^2 + b^2 = c^2 link AB = c Height = a c^2 - a^2 = b^2 0.2^2 - 0.05^ = 0.0375 root 0.0375...

1. A link is connected by two bearings A and B. The bearings run along slots which are at right angles to each other. The length of the link AB (length between the centres of bearings A and B) is 0.2m. At an instant of time, height H, is 0.05m, and the bearing A has a constant velocity V, of...