Recent content by Dacu
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Undergrad Proving Zero is Positive or Negative
Why zero , in France , can be a negative or positive number? My reasoning: 1) 0>0 involves 0=0+a where a>0 and involves 0+a>0+a and a>a and this is false. 2) 0<0 involves 0=0-a where a>0 and involves 0-a<0-a and -a<-a and this is false. So the number zero can not be negative or positive.What was...- Dacu
- Post #3
- Forum: General Math
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Undergrad Proving Zero is Positive or Negative
Good morning, How do we prove that the number zero is a negative or positive number?- Dacu
- Thread
- Negative Positive Zero
- Replies: 23
- Forum: General Math
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Graduate Equation with three consecutive prime numbers
My reasoning: From the original equation we get (n+2)^2+4np_n+4(n+1)p_{n+1}=m^2 where m\in \mathbb N^*. Is there such a natural number m?- Dacu
- Post #3
- Forum: Linear and Abstract Algebra
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Graduate Equation with three consecutive prime numbers
Solve the equation np_n+(n+1)p_{n+1}+(n+2)p_{n+2}=p^2_{n+2} where n\in \mathbb N^* and p_n , p_{n+1} , p_{n+2} are three consecutive prime numbers. ------------------------------------- A solution is n=2,p_2=3,p_3=5,p_4=7. May be other solutions?- Dacu
- Thread
- Numbers Prime Prime numbers
- Replies: 2
- Forum: Linear and Abstract Algebra
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Graduate How to Solve the Inequality x^2 + 2ix + 3 < 0?
Reason: Applications on "The fundamental theorem of algebra".- Dacu
- Post #10
- Forum: Linear and Abstract Algebra
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Graduate How to Solve the Inequality x^2 + 2ix + 3 < 0?
Hello, Inequality solutions are given by formula: x=i(-1\mp \sqrt{4-a}) where a\in \mathbb R ^-- Dacu
- Post #8
- Forum: Linear and Abstract Algebra
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Graduate How to Solve the Inequality x^2 + 2ix + 3 < 0?
Any inequality can be transformed into equality and so we can write x^2+2ix+3=a where i^2=-1 and a\in \mathbb R^-.Solving the equation is very simple ...- Dacu
- Post #4
- Forum: Linear and Abstract Algebra
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Graduate How to Solve the Inequality x^2 + 2ix + 3 < 0?
Hello, Solve inequality x^2+2ix+3<0 where i^2=-1- Dacu
- Thread
- Inequality
- Replies: 9
- Forum: Linear and Abstract Algebra