Yes I had another look at his post and I see what you mean. It seems that he forgot to take into account the fact that during a transition to the ground state the ionisation energy is radiated to the surroundings.
Of course the choice of convention makes no difference to the calculations. I never said it did. But it can be confusing whatever convention is used. Some people may look at the chosen values and think they are absolute values.
Use a different convention, let the potential energy at infinity be equal to X. We can write energy equations for the particles at infinity and at the ground state.
Infinity P.E. = X , K.E = 0
Bohr radius P.E. = X -27.2 ,K.E = +13.6, Energy lost = 13.6
Whatever convention is used...
jaumzaun calculated the kinetic energy to be negative because he thought that the potential energy at infinity really is zero instead of being at a maximum value. When he gets used to the potential energy convention he should calculate that when the atom moves to a ground separation at the Bohr...
Jaumzaun, Because we can deal with differences in potential energy only, not absolute values, we choose two things:
1. A particle separation
2. A value of potential energy for the chosen separation.
Any choices we make would be somewhat arbitrary but the most useful and logical choices, which...
I found a report from 2013 which summarised the work of a team who used the "photoionisation microscope" to observe some nodal structures of the hydrogen atom. The graphical results displayed seemed to show some agreement between experiment and theory.
I'm mainly interested to...
Specifically, how would you attempt to detect an electron, at a particular location whilst in the bound state of the hydrogen atom.
The particle detector you referred to is no good at the moment. It needs re calibrating.
Thank you but I already have a basic idea of what the Born rule is about. I was trying to point out that some of the comments made were lacking in clarity and my questions were attempts to show how some people might interpret those comments. From your response it seems that my comments in post...