Dale's latest activity
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Dale replied to the thread Undergrad Please Explain (actually explain) The Monty Hall Problem.It is relevant because it changes the conditional probabilities and the amount of information received. There is still some information... -
Dale reacted to pinball1970's post in the thread Undergrad Please Explain (actually explain) The Monty Hall Problem with
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Nice thread, I do not understand all of the explanations, especially the entropy one! (wow!) I have an explanation of why you should... -
Dale replied to the thread High School Potato paradox.One of the reasons that this seems surprising is that a 1% change seems like a small change. I think the same thing happens with... -
Dale reacted to PeroK's post in the thread High School Photoelectric and summation of photons energy with
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There is no such thing as a photon in classical EM. It's not just that the frequency of the light is the key factor. The dislocated... -
Dale reacted to cianfa72's post in the thread Graduate Topological constrains for the solutions of EFE with
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I'm keep watching the lectures on GR from F.P. Shuller and D. Giulini -- International Winter School on Gravity and Light. As far as I... -
Dale reacted to PeroK's post in the thread Undergrad Please Explain (actually explain) The Monty Hall Problem with
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This is the critical assumption/characteristic of the game. First, Monty's pick is not random (he never reveals the car); and second... -
Dale reacted to PeroK's post in the thread Undergrad Solving ##a^b## and ##b^a## via the Lambert Function with
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In school, they never taught "proof by inspection" either! -
Dale reacted to jedishrfu's post in the thread Undergrad Solving ##a^b## and ##b^a## via the Lambert Function with
Informative.
The Lambert function comes up in a lot of math videos. Here's one such video: -
Dale replied to the thread Undergrad Comparing ##a^b## and ##b^a##.Yes, good call. I am not familiar with it but you appear to be exactly right. -
Dale replied to the thread Undergrad Comparing ##a^b## and ##b^a##.If I use Mathematica to solve ##a^b=b^a## for ##b## as a function of ##a## then I get $$b=-\frac{a \ W_0\left(-\frac{\ln(a)}{a}... -
Dale replied to the thread Undergrad Comparing ##a^b## and ##b^a##.Mathematica has a function called "RegionPlot" that makes them very easy. Without the "pretty" options for the labels and the gridlines...
