Dale's latest activity

I don't see why a dipole moment anomaly would have any bearing on the monopole. Mathematically the various multipole terms are all...

This one is no less convincing than the others. Indeed as @pbuk said, this is procedurally exactly the same as what you did for the...

Thanks for your help! It appears to be quantum fluctuations in the “quantum foam.” “When scientists talk about particles like electrons...

Indeed. If the OP is satisfied that they can "derive" ## v = v_0 + at ## by plotting ## v \ vs \ t ## and observing the slope then how...

No, he says that it cannot be the one he showed (##v## vs ##t##). He didn't show ##v^2##. So all he needs is that pointer: use ##v^2##.

And the answer is very clearly yes. Like the other two equations means you can pick which quantities to plot. So plot ##v^2## and...

Yes, by multipling ##KE = KE_0 + Fs## with ##2/m##. But seriously, since eq (3) can be easily derived from eq (1) and eq (2), what is...

If you know ##v## then you know ##v^2##, but the reverse is not always true. It is mathematically possible to know ##v^2## without...

I don't see what the difficulty is. If you can know and plot ##v## then you can know and plot ##v^2##. It isn't even algebra, it is just...

I had assumed that all the graphs were obtained from experimental values.

yes, thanks much for this clarification

But that is not the only possible answer. Different authors will make different choices and they are all justifiable.

In B's frame A passed the left pole and started its clock a long time before B passed the right pole. So in B's frame the sequence is...

Just to check: you are aware that events that are simultaneous in one frame are not simultaneous in another? Your wording in the OP lead...

First, don’t use ##v=0.999 c##. It is an annoying value. Use ##v=0.6 c## so that ##\gamma = 1.25##. That is fast enough that...