Recent content by dangish

Oops.. the 4th power I did write on my test just missed it there.. and damn I can't believe I got that derivative wrong haha Thanks

question: integral of [(3-ln2x)^3]/2x my workings: I let u = 3-ln2x then du= -2/x dx so -1/2du = 1/x dx this leaves me with -(1/2)*integral of u^3/2 du I take the bottom 2 out to get -(1/2)*(1/2) * integral of u^3 du which is -1/4 * (u^4)/4 then I sub u into get -1/4...

Well actually 1/(2n+2)^(1/4) would go to zero faster so I suppose it's smaller?

I would like to this 1/(2n+2)^(1/4) is bigger.

In your example you would get 1/n^(5/4) where p = 5/4 >1 so that would converge.. correct? I realize mine could be similar... Ʃ[ 2/(n*(2n+2)^(1/4))] But I can't combine the n's on the bottom because the +2 is messing with me.

Well it sort of looks like it but I can't get it in a form to be confident with an answer

Good day.. Question: Determine whether the series is convergent or divergent: Series starts at n=1 and goes to infinity.. Of 2/(n*4throot(2n+2)) What I mean is.. 2/(n*(2n+2)^(1/4)) Can someone tell me which test to try? I can't get it in the form of a p-series.. so I think maybe the...

Thank you good sir, that might've been what I needed to hear.. Good luck with all your future endeavors as well!

They offer Mechanical here, but that's harder to get into because more people do it. :(

Hello everyone, I am in my fourth year of University and still have no idea what I want to do. I completed the first year of Engineering last year, but I did not get into Electrical because my average was just over the minimum required and all the people with better averages got in. I like...

Like I said, haven't been to class yet. I'll try and get some notes tomorrow, thanks for the help though I appreciate it man.

So it is convergent? And it's sum is 1?

Well if you got it, who cares? Haha

You are right in the sense that you need a common denominator.. Would this help? 5/(p+4) - 5/p(p-2) + 4/(p-4)(p+4)

Wouldn't both the numerator and denominator go to infinity?