Recent content by danyork

Thanks for all your help.

I used k=-mg/x (but I used 'a' for the distance instead of 'x', see my original post for the value of 'a'). After I multiplied the formula to get rid of the 1/2 I was left with: k(d^2)+2mgd=k(a^2)-2mg(-a) Then, I divided out k, but used -mg/a in place of k which gave me: d^2-2ad=a^2-2a^2...

I could get the spring constant by k=-mg/x. I divided k out of the energy equation though. What else would I use if for?

Yes, I did a copy/paste. I have a couple of friends who also didn't like the question. Are there any assumptions that could be made to finish the problem? What if we assume it's a SMH? (I'm new, so forgive me if I'm not helping the situation).

1. First let me start by saying that there are similar posts about this, but I wasn't able to figure out what I need through those. A 3.45 kg mass vertically compresses a spring 67.0 cm before it starts to rebound. How high will the Mass move above the uncompressed if the mass is left to...

Okay, thank you dauto.

Forgot to mention two things: 1. It's a little unclear, but the racket's final velocity is 0m/s. 2. I did search other forums and found some similar ones to this one, but none looking for the ball's final velocity without mentioning it's initial. Thanks in advance for any help.

Homework Statement Here is the question I'm trying to answer: A tennis player hits a 1.45 kg tennis ball with a racket of mass 2.5 kg. If he hits the ball with a velocity of 7.5 m/s and then stops, what impulse did he imply on the ball? What is the ball’s velocity? Homework Equations...