Recent content by Dave J

and y = -sqrt(20)/3 Where did you get that from. When I solved for y in the original equation. I get 0.4444 + (y^2)/4 = 1 0.55556 / 4 = y^2 Sqrt(0.138) = y y = 0.37

I did solve for y, it was 0.37 but my answer was negative and therefor couldn't be it.

Sorry that was a typo, I originally had that, and typed it out wrong.

Homework Statement The problem is Find the equation of the line with a positive slope that is tangent to the ellipse (x^2)/9 + (y^2)/4 = 1 At x=2Homework Equations Now I know that to find the tangent, I find the derivative of the equation. So I got 2x/9 + 2y/4 dy/dx = 0But its this part...