Recent content by ddobre

I think so. But I was just trying to define R in some way. I'm having trouble trying to find an equation for R(t)

No, current should remain the same since the resistors are in series with each other

Would the right loop be: 9V - 25Iright-48Iright+48Ileft = 0

Homework Statement A charged capacitor with capacitance C is being discharged through a variable resistor that has its resistance dependent on time: R = R(t). Find function R(t) if the current through the resistor remains constant until the capacitor is completely discharged and the resistance...

Is it because I1 and I3 meet at the node at the top, which then turns into I2? Almost forgot series resistors have equal current, that simplifies a lot.

Homework Statement Calculate the magnitudes and directions of the currents in each of the 3 resistors in the circuit above, if... (a) ...both batteries have zero internal resistance. (b) ...each battery has an internal resistance of 1.0 Ω. Homework Equations I1 = I2 + I3 (Node Law)The...

Homework Statement The circuit above has five resistors. Calculate the current through each. Homework Equations I1 = I2 + I3 (Node Law) ∑Vi = 0 (Loop Law) The Attempt at a Solution I tried to equate the currents using the node law, with I3 = I1+I2+I4+I5 But I see a flaw here, because the...

Could I solve for r using the equation I derived for the total resistance by relating it to P = V2/R, and then setting Req = V2/P

Each battery should have the same voltage because of the parallel configuration

If the system is open, then Vab = emf

In that case, Req = (3P + rI2)/(3I2)

If I use the equation for parallel resistors for the batteries, and they each have the same internal resistance, I end up with r/3, which would leave only two resistors in the circuit. But from the diagram, I think that they would be parallel to each other. With R equal to the above equation...

It should be: R = P/(I1+I2+I3)2

But each I would be I2

It would be equal to: R = P/(I1+I2+I3)