Recent content by Death
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Can you answer this unanswerable question?
No one created God. God has always been here. God = Infinite There is no beginning to God nor any end to God.- Death
- Post #76
- Forum: General Discussion
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Does working hard make you a good person?
Yes... no... maybe so. It really depends on the person when you come to think about it. In some respects, yes, hard working people tend to be nice/good people because they know hard it is to earn money unlike lazy people who usually live off someone else earnings. And by working hard, you...- Death
- Post #17
- Forum: General Discussion
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What Points Have a Y-Coordinate of -3 and Are 13 Units from (1,2)?
I can't get the correct answer to this problem. Find all points having a y-coordinate of -3 whos distance from the point (1,2) is 13. Thank you! -
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Log Questions: Answers to x=2 & x=10^3
I need some help on two log questions. I do understand everything of the problem until the final answer, it does not make sense. Problem 1: log3(x-1)^2 - log3(x^2 -1) = -1 + log3(x-1) 2log3(x-1) - log3(x^2 -1) = -1 + log3(x-1) 2log3(x-1) - log3(x-1) - log3(x^2 -1) = -1 log3(x-1) -...- Death
- Thread
- Replies: 2
- Forum: General Math
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Graphing k(x) = log3 (x+9): Steps to Solve
I need some help please. I'm not that good at sketching graphs out. Here's the problem. k(x) = log3 (x+9) (the number three is the base) What steps do I have to do in order to graph this problem? Thank you.- Death
- Thread
- Graphing
- Replies: 1
- Forum: General Math
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Sketch g(x)=f(x-2) + 1 = 1 + e^x-2
Thank you very much for your help Mathman.- Death
- Post #3
- Forum: General Math
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Sketch g(x)=f(x-2) + 1 = 1 + e^x-2
I'm new here and I just had a question. I can't seem to get this graphing problem. Sketch g(x)=f(x-2) + 1 = 1 + e^x-2... on a graph. Thank you very much.- Death
- Thread
- Sketch
- Replies: 2
- Forum: General Math