Recent content by Debdut

Hi, I found the solution using the method of determinants. It was not difficult. Thanks.

I am sorry for not elaborating. The equations are obtained by KCL of the above image. Here ##V_1##, ##V_x##, ##V_{in}## and ##V_{out}## are variables and all else are constants. I need to find the relation between ##V_{in}## and ##V_{out}##.

Yes, these are the equations. Thank you very much.

Here is the equation I obtain after simplification, I don't know if it is correct: gmc * V1 + s * C2 * Vout = [{s * (C1 + C2) * ro2 + 1} * Vout - s * C1 * ro2 * V1] * (s * rb * C2 + 1) / {ro2 * rb * (s * C2 - gm2)} I need to eliminate V1 to find the relation between Vin and Vout.

OK, thank you again.

Thank you very much sir. I must say that I don't fully understand the above expression. The only formulae that I have got are from this site: http://tutorial.math.lamar.edu/pdf/Laplace_Table.pdf Could you please offer some explanation or redirect me to any reference where I can learn it more?

I have two functions ##\phi(t)=\cos(\omega t)## and ##f(t)=u(t)−u(t−k)## with ##f(t)=f(t+T)##, ##u(t)## is the unit step function. The problem is to find Laplace transform of ##\phi(t) \cdot f(t)##. I have tried convolution in frequency domain, but unable to solve it because of gamma functions...

Found an article where they're saying Y(s) should be Y(s) = e-as . Laplace{x(t + a)}

Thanks for the quick reply. Do you mean e-asX(s). But that is the laplace of x(t - a). Am I wrong?

y(t) = u(t - a) . x(t) u(t) is a unit step function. I have to find Y(s)/X(s). Do I have to do convolution in frequency domain?

I'm thinking of expanding the inverse term in its Taylor series form. But it would involve terms like (x(t))^2, (x(t))^3, etc if I am right. That would lead to convolution in Laplace domain which according to me is becoming more complicated!

x(t) and y(t) are related by y(t)=1/(x(t) -k), how should I derive Y(s)/X(s)?

So how am I going to approach the parts (b) and (c). Many thanks for the above posts.

I think the distribution function will look like this, f(x)=1/20 , 10<x<30 =0 , otherwise. The problem is Uniform Distribution is a continuous random variable. The probability at a certain value of x (e.g. 10:15 or 10:25) is meaningless. It will however give probability over a range...

1. A harried passenger will miss by several minutes the scheduled 10 A.M. departure time of his fight to New York. Nevertheless, he might still make the flight, since boarding is always allowed until 10:10 A.M., and extended boarding is sometimes permitted as long as 20 minutes after that time...