Recent content by Demonfruzz

Thanks got it guys , conceptual problem

Owh sorry I made a typo I did include the v in the calculation V = 10 at x 20k=(1200*accleration - 500 ) (10 ) Acc= 2.083

Yea I thought the 2nd answer was correct because it fixes the change in kinetic energy as you had pointed out

Ao So the 2nd answer i gave should be the correct one ? Thanks

Sorry am not really sure about calculus part But maybe this is the solution Driving force =1200*acc - 500N P=fv 20kw=1200*acc - 500N Acc=2.083 2. Driving force =1200(2.083)- 500 =1999.6 Fs=0.5mv^2 - 0.5 mu^2 S={ [(0.5)(1200)(25^2)-[(0.5)(1200)(10^2)]} / driving force...

Hmm I see I will try to work it out , thanks for the help

1. Distance used from question 2. work = force x distance Force =610KJ/470 m =1297.9 acceleration = force/mass =1297.9/1200 =1.0815 2. Power x time = work Work= 20kw x 30.5 =610kj...

T tried a few but looks nowhere near promising and I don't have an answer for the question ,past year examinations

Homework Statement Mass car 1200 kg . power car constant 20kw . Resistance car motion 500N. Car passes point X and Y with speeds 10 m/s ,25 m/s. Car takes 30.5 s to travel from X to Y 1. Find acc of car at x 2.considering work/energy find distance XYHomework EquationsThe Attempt at a Solution