Recent content by Devtycoon

How can I thank you for your help?

I got sloppy with the paint tool. Sorry. It was supposed to be I.C. , the acronym for instantaneous center. Okay next fundamental question, there are 3 additional forces acting on the particle. The friction force, force due to bank angle and the normal force due to gravity. 1) Is the force...

First of all. Thanks for your help. I clearly am having a physics fundamental issue here. I have a fundamental question before I rehash the scenario here.Centripetal force is sucking the car in towards the instantaneous center of rotation right?

I am confused because the solutions states: Fc = Ff + FθThe overhead view looks like this. Right?

Car is on a 5 degree bank. Did I still mess up the FBD?

I am confused. Is my FBD messed up? I see a gravitational force in the direction of the centripetal force.

Homework Statement A car traveling 10 m/s is moving along a track banked at 5 degrees. The tire-road friction coefficient is .3 What is the minimum radius it can travel without slipping? v0= 10 m/s Bank Angle Θ = 5° μ=0.3 Note I am working through prep material for the exam. The solution...

https://www.physicsforums.com/threads/spring-constant-in-mass-spring-combinations.712165/ This thread shows how to combine equivalent spring constants in different arrangements. I was adding them all in parallel. I see my mistake now. Thanks Chet, I'll keep the questions coming.

Any particular reason?

yes, I should have put that in the problem stmt.

Homework Statement Problem: [/B] Given the mass spring system solve for k1 The natural frequency wn = 10 s-1 k1=2k2 m=1kg Homework Equations wn=(k/m).5 The Attempt at a Solution solve for k1 m x w2n =2.5k1 k1 = 40 N/mNote: I calculate 40 N/m and the solution states 250 N/m. I think I...

Homework Statement [PLAIN]http://i61.tinypic.com/10dwmtv. what is the instantaneous center of rotation for the rigid body. OA = 16 AB = 25 AD = 60 BC = 35 ωOA=2s-1 Homework Equations Vb=ωCB*BC The Attempt at a Solution I am assuming the values angles and vectors from red...

Ya I messed that up. I will begin at the node with 2i going in and i going out. It seems that I overlooked this situation. If 2 i is going in and i is going out then the 3 ohm resistor must have 1i going into that to have a KCL law satisfied.

Ok you have all helped well. I will close thread. How do I close the thread?

So the positive terminal of the battery is connecting to the ground? Sorry, I am new to circuits.