Recent content by DiamondGeezer
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Undergrad Pushing a rail truck where the mass is not constant
I think the point of the thought experiment was that the sand was supplied by a second co-moving truck traveling at v Thus for the truck, although it's mass is changing, there is no change of velocity. What happens if the truck is moving up a slope of \theta degrees? Does the truck gain or...- DiamondGeezer
- Post #5
- Forum: Mechanics
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Undergrad Pushing a rail truck where the mass is not constant
In one of my undergrad books on physics is the example of a rail truck of mass M on a frictionless railroad moving at a constant speed v, which is being filled with sand at a rate of x kg/s If force F is applied to the truck, then the truck does not accelerate because F=m \frac{dv}{dt} +...- DiamondGeezer
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- Constant Mass Truck
- Replies: 6
- Forum: Mechanics
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Graduate How did Gibbs come up with the idea that particles are indistinguishable?
I think the main reason for the lack of attention was that Gibbs published in an obscure journal in Connecticut, and most of his insights became clearer after other people had independently reproduced his results.- DiamondGeezer
- Post #5
- Forum: High Energy, Nuclear, Particle Physics
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Graduate Do black holes evaporate or go bang ?
Unfortunately the volume of a Schwarzschild Black Hole is zero using Schwarzschild coordinates, infinite if using Kruskal Szekeres coordinates (but if you include the event horizon the volume is [zero times infinity] which could be anything). This makes calculating the density of a black hole...- DiamondGeezer
- Post #19
- Forum: Astronomy and Astrophysics
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Graduate Crossing the Event Horizon of a Black Hole
Yes.- DiamondGeezer
- Post #141
- Forum: Special and General Relativity
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Graduate Crossing the Event Horizon of a Black Hole
I'm not going to stretch this thread to infinity. I'd like to pick up one comment: No, I'll take that as read. The question remains as to why so many coordinate systems have been constructed. Unfortunately black holes are not coordinate invariant. They are a product of a bad choice...- DiamondGeezer
- Post #139
- Forum: Special and General Relativity
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Graduate Crossing the Event Horizon of a Black Hole
There's a fundamental difference between the line integral of a geodesic and an "arbitrary parametrized path". Perhaps you should stop and think before making such an obvious mistake. The continuous line integral of a geodesic is always normal to the event horizon and there is no function which...- DiamondGeezer
- Post #137
- Forum: Special and General Relativity
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Graduate Crossing the Event Horizon of a Black Hole
How do you draw a line inside the horizon? In order to do that, the line must be composed of real spacelike integrals of non-zero length. But there are no spacelike integrals at all. Once again you've moved from the continuous integral outside the EH to a different integral "inside" the EH by...- DiamondGeezer
- Post #135
- Forum: Special and General Relativity
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Graduate Crossing the Event Horizon of a Black Hole
There are no spacelike paths inside the EH. Only timelike ones. But we're not in real spacetime below the event horizon. We're in imaginary spacetime.- DiamondGeezer
- Post #133
- Forum: Special and General Relativity
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Graduate Crossing the Event Horizon of a Black Hole
Now think about that. How to measure the spacetime differentials between two events each outside the causal light cone of the other? Think...think...no its gone. So the coordinates are not imaginary (and who said that they were?) but the spacetime distance between them is imaginary. Well...- DiamondGeezer
- Post #131
- Forum: Special and General Relativity
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Graduate Crossing the Event Horizon of a Black Hole
Ah, but DrGreg if there are two "disjoint" systems then there cannot be a continuous worldline that connects the infalling particle from the Universe to the singularity. But Kruskal-Szekeres has the same problem with the inner and outer integrals as I've pointed out. What K-S does is define...- DiamondGeezer
- Post #120
- Forum: Special and General Relativity
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Graduate Crossing the Event Horizon of a Black Hole
Another "proof by assertion". If there is no space to be measured, there cannot be "spacial separation". Also, there are no geodesics to the "singularity" because at the event horizon, all line integrals are normal to the spatial direction.- DiamondGeezer
- Post #119
- Forum: Special and General Relativity
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Graduate Crossing the Event Horizon of a Black Hole
At the event horizon (and below) there's no such thing as a spatial separation. All separations are (imaginary) and solely timelike - whatever that means.- DiamondGeezer
- Post #113
- Forum: Special and General Relativity
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Graduate Crossing the Event Horizon of a Black Hole
Sweet Jeebus do I have to repeat myself again? U V = \left(1-\frac{r}{2GM}\right)e^{r/2GM} becomes negative when r<2GM, which means that for an infalling particle (d\Omega^2 =0) then the dU dV also becomes negative WHICH MEANS THAT THE SPACETIME SEPARATION BECOMES IMAGINARY BECAUSE ITS THE...- DiamondGeezer
- Post #112
- Forum: Special and General Relativity
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Graduate Crossing the Event Horizon of a Black Hole
Except that you have claimed that the "signs of g_{rr} and g_{tt} are reversed" when r<2M, which is wrong. Both separations spacelike or timelike become imaginary when r<2M - they do not become the other, they become something else entirely. That is the mathematical fudge which I have been...- DiamondGeezer
- Post #110
- Forum: Special and General Relativity