Recent content by divisor

Euge, thank you. I want to check my solution by Stewart's theorem.

How to find the length of an angle bisector ($$BK$$) in a triangle $$A(1;4), B(7;8), C(9;2)$$. I calc $$BK$$: \frac{x-7}{\frac{1+\frac{\sqrt{13}}{\sqrt{10}} \cdot 9}{1+\frac{\sqrt{13}}{\sqrt{10}}} - 7} - \frac{y-8}{\frac{4+\frac{\sqrt{13}}{\sqrt{10}} \cdot 2}{1+\frac{\sqrt{13}}{\sqrt{10}}} -...