Recent content by DM1984

"(dm/dt)= (row)(pi/6)(3D^2)(dD/dt)=343(pi/4)(D^2.6)(LWC)(E)" is directly from my instructor. yes, I meant "rho". this is for graupel growth. trying to find out how long it takes for a 1mm piece of graupel to grow to 5mm. The original equation is (dm/dt)=(pi/4)((D)^2)(V(D))(LWC)(E) D=...

Homework Statement How do you differentiate this to get a change in time equation? we have: (dm/dt) = (pi/4)(D^2)(V(D))(LWC)(E) LWC = 2E-6 E=1 these two values aren't important until the very end when finding the actual time, just a plug and chug then. I'm having trouble solving for...

m=(pi/6)(density)(D^3)

So, I have a differential equation with growth problem. It is a dm/dt function and I need to get it to dD/dt, change in diameter with time. here is the original functon, dm/dt= (pi/4)(D)^2* (V(D))*(LWC)*E E=1 LWC = 2 V(D) = 343D^0.6 m/s it starts from a diameter of 1mm and grows to...

Homework Statement S=1+(a/r)-(b/r^3) Homework Equations need to find r=sqrt(3b/a) and S=1+ sqrt((4a^3)/(27b))) from a derivation of the above formula in #1. The Attempt at a Solution 0=(3b/r^4) - (a/r^2)