Differential Equation with growth

Click For Summary
SUMMARY

The discussion centers on transforming the differential equation dm/dt into dD/dt for a growth problem involving diameter changes. The original equation is given as dm/dt = (pi/4)(D)^2 * V(D) * LWC * E, with specific values for E and LWC. The user seeks to derive the dD/dt function while starting from a diameter of 1mm and growing to 5mm. A key relationship is identified: m = (pi/6)(density)(D^3), which is essential for the conversion between dm and dD.

PREREQUISITES
  • Understanding of differential equations
  • Familiarity with calculus, specifically integration and differentiation
  • Knowledge of volume flow rate equations
  • Basic concepts of geometric relationships in growth models
NEXT STEPS
  • Study the derivation of dD/dt from dm/dt using the relationship m = (pi/6)(density)(D^3)
  • Explore the application of the chain rule in differential equations
  • Learn about dimensional analysis in growth equations
  • Investigate numerical methods for solving differential equations with boundary conditions
USEFUL FOR

Mathematicians, physicists, and engineers dealing with growth models in materials science or fluid dynamics, particularly those working with differential equations and their applications in real-world scenarios.

DM1984
Messages
6
Reaction score
0
So, I have a differential equation with growth problem. It is a dm/dt function and I need to get it to dD/dt, change in diameter with time.

here is the original functon,
dm/dt= (pi/4)(D)^2* (V(D))*(LWC)*E

E=1
LWC = 2
V(D) = 343D^0.6 m/s

it starts from a diameter of 1mm and grows to 5mm and I need to find the time it takes.

I'm not asking for anyone to solve the problem and give me a final solution, but I need help in getting the dD/dt function.

I thought this was it... but its not:
multiplying by dt ___ dm = [(pi/4)(D)^2 * (v) * (LWC) (E)] dt

integrating ___ m = [(pi/4)(D)^2 * (v) * (LWC) (E)] t

dividing ___ m / [(pi/4)(D)^2 * (v) * (LWC) (E)] = t


thanks
 
Physics news on Phys.org
I don't see how you can possibly change from dm/dt to dD/dt without knowing how m is related to D.
 
m=(pi/6)(density)(D^3)
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 25 ·
Replies
25
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 52 ·
2
Replies
52
Views
9K