Recent content by donkey11

i think its only 2.5 n as i made my transformation of 45 kpa to 45000 pa

i think i have solved it by using F= pressure (pie * d/2^2) to get a value of 2.5 N, that kinda seems small but also the area is quite small could anyone tell me if this is a reasonable answer

i also have the formula p=F/Area

Homework Statement When you stiffle a sneeze, you can damage delicate tissues because the pressure of the air that is not allowed to escape can raise up to 45kpa, if this extra pressure acts on the inner parts of your 0.0084 meter diameter of your eardrum, what is the outward force...

Homework Statement Each second, a nuclear power plant generates 2000 MJ of thermal energy from nuclear reactions in the reactors core. This energy is used to boil water and produce high pressure steam at 573 Kelvins, the steam spins a turbine, which produces 700 MJ of electric power, then the...

like how do you get the value for these

where should i be calculating the distance from

well simplly is the rope is 5 meters then by what you siad 2m is equal to 5 meters... so my height would be square root of rope^2- Distance ^2

no i would say it is not because it is attached to one tree, like if i use pythagorean theorum i get a value of 5.83 m so would my height be 0.83 meters

yes i know so assuming i want to use the diagram you gave to solve for X i would take C^2= A^2 + B^2 where C is going to be height nad A is going to length of rope and B is going to be distance across ravine

okay so now I am lost 2m is the long one and x is the shorter distance 3 meters, how do i find height

yes i see what you mean by that but what is 2m, is x the 5 meters or is 2m

would be c of pythagoran theorum hich would be the value of 5.83 meters

wont the 5 meters swinging change the length of the hypoteneuse

yeah but is it a triangle ?