Calculating Force of Stifled Sneezes

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Homework Help Overview

The problem involves calculating the outward force exerted on the eardrum due to pressure from a stifled sneeze, with a specific focus on the relationship between pressure, area, and force. The subject area includes concepts from fluid dynamics and pressure calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between pressure and force, with one suggesting the formula p=F/Area. Others express uncertainty about how to begin the problem, particularly regarding missing volume measurements and assumptions about initial conditions.

Discussion Status

Some participants have attempted calculations based on the given pressure, while others question the reasonableness of the results. There is a mix of interpretations regarding the calculations and the application of relevant formulas, with no explicit consensus reached.

Contextual Notes

Participants note constraints such as the lack of temperature and volume measurements, as well as the absence of a specific textbook reference that could provide additional context or examples.

donkey11
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Homework Statement


When you stiffle a sneeze, you can damage delicate tissues because the pressure of the air that is not allowed to escape can raise up to 45kpa, if this extra pressure acts on the inner parts of your 0.0084 meter diameter of your eardrum, what is the outward force?


Homework Equations


work= Pressure * Volume
Force= work/ circumference
pv=nRT

The Attempt at a Solution



i have no idea where to start, i know that pressure is related to work by volume but i do not have any measurements for volume, i know i can get volume but i do not know temperature or amount of moles, i know i can said p1v1=p2v2 but i do not know the original pressure or original volume to make that assumption. I just need to know what to look at to start the problem Thanks!
 
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i also have the formula p=F/Area
 
i think i have solved it by using F= pressure (pie * d/2^2) to get a value of 2.5 N, that kinda seems small but also the area is quite small could anyone tell me if this is a reasonable answer
 
Your pressure seems to be correct this corresponds to a mass of about 250 grams. Quite a lot for such a delicate membrane would'nt you think?
 
Is it 2.5 kN?
 
i think its only 2.5 n as i made my transformation of 45 kpa to 45000 pa
 
There is an example in the textbook.. the one by knights jones and field.. is that what you're using? anyway, there was an example in the book where it was Pa multiplied by meters squared and equaled Newtons... i don't have the book or else i'd tell you the page!
 

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