Recent content by DonutHole

in that case the answer would be 0.57

so the equation would be ma = F - mg sinθ - μmg cos θ

I see so if that isn't the problem what do you think I got wrong?

that's what i thought too maybe it should have been 524 + the rest instead of -?

the answer and step I got are: ma = F - mg sinθ + μmg cos θ 53(1) = 524 - (53)(9.81)sin22 + μ(53)(9.81)cos22 53 = 329 + 482μ μ = -0.57 is this correct?

Yes the applied force is parallel to the ramp. I should have shared this free body diagram earlier

This is my first time doing a question like this so I am not too sure but the equation ma = F - mg sinθ + μmg cos θ is correct? and if that's the case what is F?

shouldn't friction be acting towards the bottom of the slope because applied force is acting towards the top?

I think the equation should be Fa - mg sinθ + μmg cos θ a in Fa is the acceleration and Newtons 2nd law says that the external forces applied should equal ma which means that all the components of the equation should equal mass times acceleration?

I am not sure how to incorporate the acceleration of 1m/s^2 into the equation.

Fn = 53 X 9.81 X cos 22 Fnet = 524 – 53 X 9.81 sin 22 + μ X 53 X 9.81 cos 22