Recent content by Dorian

I'm aware :) Thanks! I'm more concerned that the textbook had a wrong answer (if this is in fact the case), which made me question my understanding in an unproductive way.

Thank you both for your help! And yes, the cos is what's in the textbook, although I remember from a trigonometry textbook I used once upon a time that both cos and sin can work.

Homework Statement [see attached photo] I seek specific help with (a) only. The answers to this question are provided in the back of the textbook, so I know the answers (I hope). Homework Equations ##x(t)=Acos(\omega t+\phi _{0}),## ##v_{x}(t)=-A\omega sin(\omega t+\phi...

Apology accepted. =) I am truly appreciative of your prompt responses and your help. Thank you, sincerely. :smile:

Goodness. That was a little condescending and I've been nothing but respectful toward you. :/ In anyway event, I used different reference heights for the two masses. If I gave both ##PE_{m10}## and ##PE_{m20}## zero potential energy for both of their starting positions, then the final potential...

They're from the Conservation of Energy equation, and what you stated is precisely what I did. I'm sorry you didn't interpret it the way I intended it to be interpreted. What I provided wasn't the complete product, merely me looking for a comment on if this part of my derivation made sense, not...

edit: I think I figured it out: ##h_{1}=\Delta s## and ##sin(30^{\circ})=\frac{h}{\Delta s}\rightarrow {\Delta s}=\frac{h}{sin(30^{\circ})}=2h## As such, ##PE_{0}=PE=3mgh=mg\Delta s\rightarrow 3mgh-mg\Delta s=3mgh-mg(2h)=3mgh-2mgh=mgh## Now for Conservation of Energy (as simplified earlier)...

Sure thing! Thank you for the prompt responses, by the way. :) I think the issue for me arises in the potential energy. For the right side of the equation, I have ##\frac{1}{2}3mv^{2}+\tfrac{1}{2}mv^{2}+\frac{1}{2}(\frac{1}{2}2mR^{2})(\frac{v^{2}}{R^{2}})=\frac{5mv^{2}}{2}##. But the right side...

I didn't carry it because ##T_2=3mg\sin \theta-3ma=3mg\sin(30)-3ma=\frac{3}{2}mg-3ma##

Homework Statement [please see attached photo] Homework Equations [please see attached photo] The Attempt at a Solution [please see attached photo] The issue for me starts with (but probably doesn't end with) replicating the velocity equation using the Conservation of Energy equations. Is...

I've searched the forums from time to time, but figured I'd finally open an account here. I'm almost completely new to physics, but I find it fascinating and wish to learn more, despite the struggles. As of now, I'll be entering my first intro to physics course this fall, but have been studying...