Recent content by doublea500

actually, could i just find the Rt then find the Current in total. and then like separate it using proportions? like say the Rtparallel was 2 and the Rtseries was 2. and Rt in all was 4. Let's say V=8. I am just making this up now, so you don't get confused with the pic on top. so i could...

i believe you have your formula wrong p1=p2. M1V1i+M2V2i=Vf(M1+M2)

so just replace from with through then :D. and how do i find the voltage and current Through these resistors without effective resistance?

Homework Statement See picture. Homework Equations Ohms Law-V=IR The Attempt at a Solution i do not know what to do once i find Rt (8.714...) because there is a parallel and a series in this circuit...

just a quick question about ohms law (v=ir) concerning when there is a parallel and a series in the same circuit. i know the rules like in a parallel, v total is v1+v2... and in a series it is 1/v+1/v2=1/vt. and that's the opposite for Current. but what do i do when there is a series and a...

Homework Statement 1. There is a counterclockwise current I in a circular loop of wire situated in an external magnetic field directed out of the page as shown above. The effect of the forces that act on this current is to make the loop (A) expand in size (B) contract in size...

nevermind, i found it out. thanks for the help

like what I am trying to ask is if you do V=IR would it be 9V=1.5A*R1 and then you could find r1 like that?

is what i wrote correct?

Homework Statement Question asks for a lot of stuff... Total Resistance Total Current R1, V1 < V2, I2 <----- R=resistance V=Voltage I= Current 1 is resistor 1, 2 is res2... R3, I3 < Homework Equations...

not 100% on this but here's my help. id do r3,4 in a series, then Rt of that with r5 in a parallel. then the rt3,4,5 with R2 in a series. r7 and r6 are a series so just add those. then i believe you can just do the 3 final resistances all in one parallel circuit.

hmm, couldn't you do it that way then "simplify" it to a series circuit so I is constant. then can't you do V=IR and plug in 9 for Itotal and whatever the total resistance was for R and find V total? only problem here is S though.

ok, how bout I1=I2+I3 whereas I1 is amp for 3 ohm resistor, I2 is amp for 6 ohm resistor, i3 is amp for 1 ohm resistorSo here's the formulas i have so far. 12=3I1+6I2 6=3I1+I3 I1=I2+I3 Ahh i got it... here's what i did, tell me if there's a simpler way. i combined these formulas. and used...

id try combining the furthest resistances to the right because it is a series circuit, to get 9S then finding the total resistance of that and 2S which is 1/9S+1/2S=1/Rt ->2/18+9/18->11/18->18S/11= Rt. then find the total resistance of that and4s because its a series circuit. so its 18S/11 +...

so 3I1=6I2+1I3? i keep using the loop rule but i am getting nowhere Also, should i be using the same I or different Is like I've been doing?