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A material with an index of refraction of 1.44 is used to coat glass. The index of refraction of glass is 1.5. What is the minimum thickness of the coating that will minimize the reflection of light with a wavelength of 4680 A? Answer in units of µm. I know that the thickness for this is t =...

I did the part 1 and got 3.15 V which is right. I used the equation (V)(2.718)^(-t/RC) And for part 2 I derived the equation (((V/(R1+R2))8((2.718)^(-t/(R1+R2)C)))*R1 but I am getting the wrong answer. Please Help!

017 (part 1 of 2) 10 points For a long period of time the switch S is in position "b". At t = 0 s, the switch S is moved from position "b" to position "a". Find the voltage across the 1 MΩ center-left resistor at time t1=5s. Answer in units of V...

I got it thank you very much for helping me.

q1 = -q2 q3 = 2*q1

So [(q1+q2) /(4*π*ε0*r2)] = [q3/(4*π*ε0*r2)] Does q2 + q3 = 64.0681 µC

Inside are q1 and q2. Outside are q3

So the charge contained within the Gaussian surface = q1

So how do I apply Gauss Law to find q2 and q3 without knowing either E nor r? P.S. I know I am asking very basic stuff but I just learned the concept and I haven't fully understand on how to use Gauss Law properly yet.

Oh! I got it. Thank you very much.

I used E = 0 but then q2 = 0.

Yes if I apply Gauss' Law E = q/(4*π*ε0*r2) but I don't know both E and r. and if I use E = 0 wouldn't that make q2 = 0

So use the equation α*r3/(3*R*ε0) where r = 15.2 cm and R = 18.4cm?

Yes but the only formula that I know on how to find qenclosed is qenc= [(2*π*l)*(α*r3)]/(3*ε0) and when I finally derive the equation I end up with the same as the one from part b.

I know that the field within a conductor is zero. But I need the charge of the inner an outer surface of the shell.