Recent content by DrMcDreamy

Okay, that's wrong, I only have one more chance to put in the correct answer, so how would I do this?

So would it be: \epsilon+(1.69x3.54)+(9.34x3.54)+(5.66x3.54)+(1.74x3.54)+11.88v=0 \epsilon=-77.44

Homework Statement What is the emf E of the battery at the lower left in the figure? Answer in units of V. http://img508.imageshack.us/img508/6/82852928.png Can someone guide me? I'm confused as to where to start. I think I am supposed go the route of the loop, but I am given the...

The answer I had gotten (2.03e6) is wrong. Why?

Homework Statement This is a two part problem: 3- A conducting spherical shell of radius 19 cm carries a net charge of −8.15 μC uniformly distributed on its surface. Find the electric field at points just outside the shell. (Take the radially outward direction to be positive.) Answer in...

I have a similar problem here's my work but its wrong cause its not one of the answer choices: Problem: Consider the setup of the two-lens system shown in the figure, where the separation of the two lenses is denoted by d = 1.5 a. Their focal lengths are respectively f1 = a and f2 = 2 a. An...

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Thank you! My work: 3\frac{1}{f}-\frac{1}{-3f} = \frac{3-1}{3f} = \frac{4}{3}f (inverse) = \frac{3}{4}f

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Homework Statement This is a 2 part problem but I figure out the first part. Heres the 1st problem and the solution: 7- Given a convergent lens which has a focal point f. An object is placed at distance p = \frac{4}{3}f to the left of the lens. See the sketch. Solution: q1 = 4f, and is a...

Homework Statement This is a 2 part problem: 4- A person is to be fitted with bifocals. She can see clearly when the object is between 49 cm and 1.5 m from the eye. The upper portions of the bifocals should be designed to enable her to see distant objects clearly. What power should they...

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I figured it out ^thanks

So it would be: \theta3=180-(26+26+90)=38\circ n3sin\theta3=n4sin\theta4 1.69sin38=1.33sin\theta4 \frac{1.0405}{1.33}=sin\theta4 sin-10.7823=\theta4 51=\theta4 And #3 is right? TIA