As far as the break line. You proved it false, so the break would kill the for loop. This would be a faster and optimal code to get it out of that for loop.
Take numb = 1 billion, 2 would prove it not prime. Your break command got it out of that for loop within 1 iteration. However without it...
A breadth first search would hit the nodes top down. You could check if its a leaf as you go top down. Stop it once detected. Never coded a breadth first to help much further than that.
Use your example of 0-10 adding up the digits to be 55. Do you have to rewrite your for loop to solve the same thing for say 0-15? 0-50? 0-100?
Would you want to use this for loop for 0-10 as a function that accepts different values of X, where x=10 means sum up all the digits up to 10 and...
I suggest testing the first guess outside the while loop
x0 = (y/4);
x1 = (x0+(y/x0))/2;
while (!( x1 - x0 <= 0.0001 && x1 - x0 >= -0.0001))
It will enter the loop if it wasn't divisible by 4. Now you need a new guess to use. Update your guess x0 = something.
Then you can try your formula...
x1 = ((x0 + (y/x0))/2);
x0 = x1;
in normal terms:
x1 = calculate a new value
x0 = update me to that new calculated value
Now x0 holds the same value as x1
When you print them out, you confirm this.
Which means your while loop is seeing X1-X0 (BOTH BEING EQUAL) = 0
This breaks the while...
Homework Statement
An avl tree typically balances with a balance factor of -1, 1, 0.
What if the tree allows -2,-1,,0,1, 2 as a balance factor. Prove or disprove that the height of the tree is logarithmic to the number of nodes O(logn)
Homework Equations
Normal balanced AVL tree everyone...
I figured out the z axis part since it forms a right triangle. I can't wrap my head around how I would measure the potential at a point not on the z axis.
Homework Statement
A thin disk of radius R consists of a uniformly distributed total charge Q. The disk lies a distance D above a grounded perfectly conducting plane. The disk and the plane are parallel. Set the conducting plane in the x-y axis, and the z axis through the center of the disk...