Recent content by E=mc^84

I agree:)

Uhe formula for work: W = Fdcos37*, solve for d by assuming that the mass starts from rest.

In Physics, the SI unit for mass is the Kg. In chemistry, it usually is grams but it also depends on the type of questions you do and what S! unit the question asks for.

Hi, I am no expert ,but i think you solve for v like you did with PE=KE, and that equla that initial velocity of the mass leaving the spring. After you get that, you use the incline formula for acceleration: ma = -mgsin38, so, a = -gsin38. Then The object reaches a max height so V2 = 0: V2^2 =...

Einsteins intrepertation of time is that time is simply the foward process of electricity turning into magnetism viceversa. If there was no observer to observe light itself, time, in this sense would not exist.

Sorry , but that solution is if the bottom block is moved without the top block moving, my mistake. I am no expert at this, just trying to help. Ya, so in 1) If you want to get the system moving by just pushing on the top block then the force needed for that is just the force of friction of the...

You forgot to plug in friction b/w the floor = 0.22(7kg)(9.8) = 15N, therefore Fnetx = Fa - Ffriction, where Fa = max force needed, therefore Fa = 3.92m/s2(7kg) + 15N = 42.44N :)

How would these black holes distribute themselves in the universe today if they were created in the beginning stages of the universe? Note: I am assuming that the black holes were created in the initial stages in the formation of the universe.

Yup, looks right:)

Its neglected since the same acceleration is needed to move the box 1.0m.

This question is quite long to write out so ill briefly explain: You have to isolate the the top block and get the acceleration of just that block. Then, you use this acceleration for the bottom and the top block m1+m2 = 7kg total and you shud get the maximum force needed. Hope this helps:)

Im no expert, i worked it out and this is what i got: You deduced the first part right, so a = 1.5m/s2, then the weight of the box = 3000N, so mg = 3000N, so the force of friction = uk(3000N). If you use Newtons third law the foward force = the reaction force, so it is constant motion. So, the...

NO, Vinitial shud equal = sqrt2gx = sqrt2x9.8x0.2 = 2m/s

No, you have to find Vo. Yes, you use gavitatinal accelertion cus the dog jumps vertically. use: vfinal^2 = Vinitial^2 - 2gx, Vfinal = 0 since the dog comes to an abrupt stop at the 0.2m height. Therefore, solve for Vinitial. Hope this helps;0

What if we can observe it indirectly lke we do with black holes?