Mass-spring system on an incline

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SUMMARY

The discussion focuses on a mass-spring system on a frictionless incline, where a spring with a constant of 565 N/m is compressed by 15 cm to propel a 5.4 kg mass. The key equations used are potential energy (PE = 1/2 kx²) and kinetic energy (KE = 1/2 mv²). To find the velocity of the mass when it leaves the spring, the conservation of energy principle is applied, followed by using the incline's acceleration formula (a = -g sin(38°)) to determine the maximum distance the mass will rise. The correct approach involves solving for initial velocity and then applying kinematic equations to find the distance.

PREREQUISITES
  • Understanding of potential energy and kinetic energy equations
  • Familiarity with the concept of conservation of energy
  • Knowledge of basic trigonometry, specifically sine functions
  • Ability to apply kinematic equations in physics
NEXT STEPS
  • Study the conservation of energy in mechanical systems
  • Learn about kinematic equations for motion on inclined planes
  • Explore the effects of spring constants on motion dynamics
  • Investigate the role of angles in energy transformations
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Students studying physics, particularly those focusing on mechanics and energy systems, as well as educators looking for practical examples of mass-spring interactions on inclined planes.

easchwen
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Homework Statement


A spring is mounted at an angle of = 38 on a frictionless incline as illustrated in the figure below. The spring is compressed to 15 cm where it is allowed to propel a mass of 5.4 kg up the incline. If the spring constant is 565 N/m, how fast is the mass moving when leaves the spring? To what maximum distance from the starting point will the mass rise up the incline?


Homework Equations


PE=1/2kx^2 and KE=1/2mv^2



The Attempt at a Solution


I honestly don't know. I tried using PE=KE with the formulas above, and then tried adding in the cos(38) to the KE side, but I could not get the correct answer. Help?
 
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easchwen said:

Homework Statement


A spring is mounted at an angle of = 38 on a frictionless incline as illustrated in the figure below. The spring is compressed to 15 cm where it is allowed to propel a mass of 5.4 kg up the incline. If the spring constant is 565 N/m, how fast is the mass moving when leaves the spring? To what maximum distance from the starting point will the mass rise up the incline?


Homework Equations


PE=1/2kx^2 and KE=1/2mv^2



The Attempt at a Solution


I honestly don't know. I tried using PE=KE with the formulas above, and then tried adding in the cos(38) to the KE side, but I could not get the correct answer. Help?


Hi, I am no expert ,but i think you solve for v like you did with PE=KE, and that equla that initial velocity of the mass leaving the spring. After you get that, you use the incline formula for acceleration: ma = -mgsin38, so, a = -gsin38. Then The object reaches a max height so V2 = 0: V2^2 = V1^2 + 2ax, and solve for x!

Hope this helps:)
 

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