Recent content by eefje

  1. eefje

    Potential energy -- child sleds down a slope and comes to a stop....

    But how do i come to the Right solution ? What did i do Wrong in the latest answer i gave, and not only the positive of negative sign
  2. eefje

    Potential energy -- child sleds down a slope and comes to a stop....

    N1=23*9,81N*cos(35°) = 184,8 Fw1= Fn*0,1= 18,48 N2=23*9,81=225,63 Fw2=Fn*0,1=22,563 (hB= cos55°*25=14,34) Epot=-Fw.d 23*9,81*14,34=-18,48*25-22,563*d 3235,53=-462-22,563*d 3235,53+462=-22,563*d 3697,53/-22,563=d 163,87=d
  3. eefje

    Potential energy -- child sleds down a slope and comes to a stop....

    I have tried it with Epot=-Fw.d with TWo different FN but the solution is wrong
  4. eefje

    Potential energy -- child sleds down a slope and comes to a stop....

    Thank you very much I understand it now :smile:
  5. eefje

    Potential energy -- child sleds down a slope and comes to a stop....

    Thank you :) but where is the friction 0,1 then? I will try to solve it an other time because I have tried it and i can't solve it maybe another time with the help of the things you have said
  6. eefje

    Potential energy -- child sleds down a slope and comes to a stop....

    Is there only friction on the flat?. I have put the friction of the slope =0 and changed everything in the thing I have post and I come still on 174,86
  7. eefje

    Potential energy -- child sleds down a slope and comes to a stop....

    Thank you! you mean just: m*g*h=-Fw*d 23*9,81*14,3=18,48 d=175,08 it isn't right is mine hB right?
  8. eefje

    Potential energy -- child sleds down a slope and comes to a stop....

    Thank you very much ! I have changed the numbers now of the degrees but I don't understand what I have to do now
  9. eefje

    Potential energy -- child sleds down a slope and comes to a stop....

    Homework Statement A child starts from rest and slides on a sled first slope down over a distance of 25 m . Then, the child slides further over a horizontal plane. The angle of inclination is 35 ° and the kinetic coefficient of friction between the sled and the snow is 0.100. The mass of the...
  10. eefje

    Calculate the total stopping distance of the car

    Thank you very much, I can solve it now. the 1/2 was a stupid mistake, but I didn't know that the distance in the 0,5 s important was. Thank you :)
  11. eefje

    Calculate the total stopping distance of the car

    you mean in the 0,5s ? Δv= Δx/ Δt and after that: Δx= a*Δt^2+Δv*t Δv=a*Δt
  12. eefje

    Calculate the total stopping distance of the car

    Hey Thank you for helping me, I will do it right the next time. In the 0,5 s he travels 6,945m i think (13,89*0,5). But I still can't solve it
  13. eefje

    Calculate the total stopping distance of the car

    Homework Statement reaction time of a driver to brake is 0,5s in that time the speed is constant the speed of a car is constant when he decides to slow down and to stop with -6,0 m/s2, the initial speed is 50 km/h Calculate the total stopping distance of the car Homework Equations Ve= -6,0*t...
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