1 2 3
4 5 6
7 8 9
construct 12369874
or 123654
or 5698
divide 12369874 by 1111 = no remainder
divide 123654 by 111 = no remainder
divide 5698 by 11 = no remainder
or, arrange them in a cube:
5 6
1 2
7 8
3 4
construct 1562 / 11 = no remainder...
has anyone investigated the three-d scattering of numbers?
FYI:
for any base
take the symbols that represent the numbers
arrange them in a rectangular or square grid
from a starting point, follow them in a square, rectangle, or diamond until you construct a number of 2n digits...