Recent content by EGill

ln\left[\frac{u-x}{((u-x)^2+1)^{1/2}}\right]=e^{ln\left[x\right]+c \frac{u-x}{((u-x)^2+1)^{1/2}}=Dx Would this be correct? Since C is a dummy variable i figured I could reuse it, but I see your point. Also, this was my first time trying to type a formula into the reply...

Thanks for the response. Took forever, but I have managed to do it correctly further along now. I am still stuck at another point. The new attachment shows all my work again

I have attached a word document that shows all the work and equations. Your help is appreciated.

Wow, thanks so much. The cancelling of dz was part of what was confusing me. Also, I was just looking at the diagram incorrectly for no particular reason, but since I saw it wrong initially I could not get it out of my head. Also, how do you type formulas into this forum?

I really need help understanding how the book created the equation from the book. I would really appreciate help understanding it. The attachment shows an image and the equation.