Recent content by Elara04

Sorry, 10500 is force in newtons instead of kilonewtons, 8.9m is the height, 13.9 is theta. I was using w = F x H / sin theta + mgh, although i'm not entirely certain whether that equation is correct

I'm unsure on where to begin with this question, i've tried many different formulas that aren't giving me the right answer. I believe to start I need to convert the kilo newtons to newtons. I tried w = fs + mgh w = 10500 x 8.9/sin(13.9)+(1845.69 x 9.8 x8.9) = 549986.46 J and then convert to...

Summary: Hey, I'm getting confused with this question and don't think I'm doing it right, I was wondering if anyone could help me Tides vary so the high tide and low tide height of the water is different every day. At certain times of the year, such as a Spring tide, the water can be very deep...

The point (1, 5) is on the curve: y=ax^2+bx+c. This point gives the linear equation: 5 = a + b + c. A second point on the curve, (2, 10) gives the linear equation 10=4a+2b+c. A student called Erika thinks that the point (2, 19) is also on the curve. 5 = a + b + c. 10=4a+2b+c 19=4a+2b+c the...