Recent content by Elisabeth_91

I know 0.5F is huge. But can you tell me how to calculate it correctly? I thought that in this case the transformer ratio question can be solved independent from the question of the capacitor.

What about the transformer ratio, was this thought correct? Thank you very much!

Thank you very much for your quick reply. So you mean: I,load = P / V,dc = 12W / 5V = 2.4 A Q,c = I,load / (0.5*T) = 2.4 A * 0.01s C = Q/U = 0.024C / 0.05V = 0.48F Is this the correct way? Is it coincidence that is the same result as with my first approach?

ii) diode configuration Full-Wave-Bridge iii) capacitor value http://en.wikipedia.org/wiki/Ripple_(electrical)#Time-domain_ripple Can I use this simplification here? V_{ripple} = \frac{I_{load}}{2fC} P = I_{load}*V_{dc}

i) transformation ratio In the end I want a DC Voltage of 5V. Using a full-wave bridge this means V_{dc}=\frac{2 V_{2,max}}{π} V_{2,max} = \frac{π V_{dc}}{2} = 7.85V Since I need a transformer that is giving this peak voltage Transformer ratio = \frac{V_{1,max}}{V_{2,max}} =...

Would it also be possible to use just a Capacitor Filter, this seems to be the easiest way to solve the problem. Like shown here: http://www.tpub.com/neets/book7/0249.GIF What is the advantage of the bridge?

I need to use a full wave rectifier bridge with a Capacitor parallel to my load. Is this correct? What I don't understand is, do I put a normal transformer before the bridge?

Homework Statement A classical rectifier is to be designed to provide 5V +/- 1% for a logic circuit, with output power of up to 12W. The input is conventional 220V, 50Hz source. i) Choose a transformer ratio ii) Choose a diode configuration iii) Calculate the capacitor value to meet the...