Recent content by EmBista

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    Engineering How to Analyze a Diode Circuit with Multiple Voltages

    All the questions prior to this one assume the voltage drop across Si is 0.7V, and Ge is 0.3V. But I do know about the V-I characteristics. However, I know about Shockley's equation: I=I0(exp(qVa/kT)-1), haven't seen i ~ i0exp(V/26mV) before. In this case I guess I should write a range of...
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    Engineering How to Analyze a Diode Circuit with Multiple Voltages

    Ok so when ignoring the Si diode the voltage at Vo1 is 13.4V, >0.7V therefore it is conducting so looking at the whole circuit. I could be completely confused, but because Si diode is parallel to R2+Ge diode, is the total voltage drop across R2&Ge diode only 0.7V? edit: so Vo1=0.7V and...
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    Engineering How to Analyze a Diode Circuit with Multiple Voltages

    Homework Statement Find voltage at Vo1 and Vo2 The left part is the schematic used in the question. The right side is the engineering schematic I drew up. The Attempt at a Solution I'm not sure what to do here. because there is a Si and Ge diode that means the Ge will be actived first...
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    Common Emitter Amplifier Design

    I increased RL to 13.08K and now it's a lot closer to 4Vp. But I am a little confused. Shouldn't each value be able to be calculated in order to reach the requirement of an 8V peak-to-peak output. In the end the only real assumption was the value of Rload which I just made really large. I...
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    Common Emitter Amplifier Design

    ok so rE=1360/20=68 then RE=300-68=232 This gives a nice sinusoidal symmetrical output, however it is only 3.6V peak to peak. that is only a gain of about 9
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    Common Emitter Amplifier Design

    so, at Vin=0.02V Vout is 4.891V peak-to-peak. Gain is 122.275 obviously way to high. Add an unbypassed resistor to the emitter? but how does that work thenAre the calculations that I did for R1, R2, RC, RE all correct?
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    Common Emitter Amplifier Design

    But I need to run the simulation, so what do I do then? where do I measure the collector voltage? is it before the capacitor C2? in that case it is the same waveshape shifted up. the same wave going between +14V and +2V
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    Common Emitter Amplifier Design

    Yes that's R5 I calculated. So are you saying the way I calculated it was wrong? In that case what are the things I should find in order to find R5 and what are the formulas associated? I put some number in for the capacitors (pretty sure they are wrong though) and got an output that peaks...
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    Common Emitter Amplifier Design

    considering the base current I found R1 to be 1.735kΩ. Those lecture notes look sort of familiar. The one you gave is a lot more clear though. one question though, those describe r_be=(h_fe+1)(0.025/I_E) whereas my lecture notes simply say r_e=0.026/I_E. anyway, I found Rl using your...
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    Common Emitter Amplifier Design

    perfect description of my lecturer. [/PLAIN] Ok so Vin=0.4Vpp (peak-to-peak), Vout=8Vpp so Gain=8/0.4=20 don't think so. to continue on the design.. starting from scratch. How do I know what the circuit will look like. As described in the OP I have R1 and R2 and R3=Rc (collector) and...
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    Common Emitter Amplifier Design

    Thats not a typo. Now I'm more confused though.. :confused:
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    Common Emitter Amplifier Design

    Isn't the gain: A=Vout/Vin A=8/0.2 A=40
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    Common Emitter Amplifier Design

    I think I should only worry about the capacitors after I have correctly found all the resistor values? is that correct? A1: I can just leave it like 1.36kΩ A2: The input is 0.2V sinusoidal. The output should be symmetrically 8V. I'm not 100% sure i got the correct values for R1,R2, Re...
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    Common Emitter Amplifier Design

    Homework Statement I have to design a Common Emitter Amplifier using a 2N2222 NPN transistor and an 18V DC supply. The specifications are as follows: Should be stable for variations in forward current gain, β. The input signal to the amplifier is a 0.2 Vp sinusoidal signal, at a frequency of...
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    Sinusoids and Phasors (Micro-Cap)

    In MicroCap we were supposed to draw the circuit and measure the voltages and estimate the phase angle. I did this correctly, however for the voltage across the capacitor I calculated it to be 1.878∠-86.32°V but when I look at the graph and I calculate the voltage drop (2.64-3.049=-0.409)...
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