Recent content by embury

The above answer is pretty good. But if you preform row operations on the matrix: [0 2 3 : 0] [0 4 6 : 0] [0 6 4 : 0] you get: [0 2 3 : 0] [0 0 0 : 0] [0 0 -5 : 0] from this you get: -5c = 0 c=0 2b+3c=0 b=0 x is a free variable, so a = s you then get: s x [1] [0] [0]...

Thank you. I guess this question isn't that difficult. For some reason I thought it was harder than it was. :blushing: Thank you guys.

Homework Statement I need to find the equation for the line that passes through the pont (-1, 2, -3) in the direction of the vector (1,-1,-1) Homework Equations The equation needs to be in the form v(t)=v subscript 0 + tv The Attempt at a Solution I know how to find the equation of...

Thank you for your help, I think I understand. If not, I'll be back. :biggrin: Thanks again.

The definitions we were given are: Injective: A linear transformation T: R^p -->R^m is injective (one to one) if and only if the equation Tx=0 has only the solution x=0. Surjective: If T:R^p --> R^m is linear then T is surjective if and only if the system Tx=b is consistent for all...

I am extremely confused when it comes to linearly transformations and am not sure I entirely understand the concept. I have the following assignment question: Consider the 2x3 matrix A= 1 1 1 0 1 1 as a linear transformation from R3 to R2. a) Determine whether A is a injective...