The task is completely theoretical, it said that the whole nuclear power plant industry had made 11,5% of the whole production of electricity which is equivalent to 2.49 PWh (in 2016).
Hey so I got another question. Is it correct for me to divide the energy in Joules equivalent to 2.49 PWh on 0.35 as it stands for 35% efficiency for the power plant?
I was told to do so when calculating things related to nuclear physics. However does it seem logical that it would take so many kilograms of uranium 235 to create 2.49 Peta Watthours? I know that peta is a huge number but would it really take so much mass to create this much electricity?
I first converted 2.49 PWh to Joules and got 8.964*10^18 Joules. Divided this value by 0.35 as that's the efficiency of the power plant and got 2.561142857143*10^19 Joules. As mentioned earlier I found out that single a fission makes 2.5977713481*10^-11 Joules. Divide the required energy by the...
Hey, thanks for the suggestions guys. I've figured out that the energy released per uranium atom may variate quite a bit based on the sources where you find the atomic weight from. I used https://periodictable.com/Isotopes/056.141/index.html to get my numbers and got 2.5977713481*10^-11 Joules...
I've calculated that reaction-energy in fission of a single atom of Uranium-235 is 2.5977713481*10^-11 Joules (based off of the equation given above.) I'm assuming that PWh has to be converted into simpler units so, 2.49PWh = 2.49*10^15Wh.. afterwards I could make it into watts but I was never...
I have just started learning physics at school. The reason why I turned to this forum, is that I can't always keep up with the school and their competence aims as the teacher usually rush us through the learning material.