Recent content by eminem4002

  1. E

    Nuclear Power Plants - Electricity Production

    The task is completely theoretical, it said that the whole nuclear power plant industry had made 11,5% of the whole production of electricity which is equivalent to 2.49 PWh (in 2016).
  2. E

    Nuclear Power Plants - Electricity Production

    If I was to multiply the value then it would just tell me what 35% of that energy is.
  3. E

    Nuclear Power Plants - Electricity Production

    Hey so I got another question. Is it correct for me to divide the energy in Joules equivalent to 2.49 PWh on 0.35 as it stands for 35% efficiency for the power plant?
  4. E

    Nuclear Power Plants - Electricity Production

    Okay so I also searched up and you're right! Thank you for the assistance!
  5. E

    Nuclear Power Plants - Electricity Production

    I was told to do so when calculating things related to nuclear physics. However does it seem logical that it would take so many kilograms of uranium 235 to create 2.49 Peta Watthours? I know that peta is a huge number but would it really take so much mass to create this much electricity?
  6. E

    Nuclear Power Plants - Electricity Production

    I first converted 2.49 PWh to Joules and got 8.964*10^18 Joules. Divided this value by 0.35 as that's the efficiency of the power plant and got 2.561142857143*10^19 Joules. As mentioned earlier I found out that single a fission makes 2.5977713481*10^-11 Joules. Divide the required energy by the...
  7. E

    Nuclear Power Plants - Electricity Production

    Hey, thanks for the suggestions guys. I've figured out that the energy released per uranium atom may variate quite a bit based on the sources where you find the atomic weight from. I used https://periodictable.com/Isotopes/056.141/index.html to get my numbers and got 2.5977713481*10^-11 Joules...
  8. E

    Nuclear Power Plants - Electricity Production

    I've calculated that reaction-energy in fission of a single atom of Uranium-235 is 2.5977713481*10^-11 Joules (based off of the equation given above.) I'm assuming that PWh has to be converted into simpler units so, 2.49PWh = 2.49*10^15Wh.. afterwards I could make it into watts but I was never...
  9. E

    Balance these nuclear equations

    True that, thank you for the help!
  10. E

    Balance these nuclear equations

    Alright, turns out the task was indeed incorrect and the correct answer is beta decay of Cobalt-60.
  11. E

    Balance these nuclear equations

    Great! I was thinking so too, maybe the creator of this task has written it wrong, I'll ask him and come back to this discussion later.
  12. E

    Balance these nuclear equations

    Are you sure? Because on the website it says that there's an electron antineutrino as the byproduct and not an electron neutrino as I wrote.
  13. E

    Balance these nuclear equations

    Ok, so I think I figured it out... Is this correct?
  14. E

    Balance these nuclear equations

    I was thinking that these reactions have something to do with the conservation of leptons but I am not certain.
  15. E

    Struggling with Physics? Join Our Community of Learners!

    I have just started learning physics at school. The reason why I turned to this forum, is that I can't always keep up with the school and their competence aims as the teacher usually rush us through the learning material.
Back
Top