Thank you very much for clearing that up - it makes a lot of sense. I hope you don't mind me asking another question, but in the formula:
##x'=##\gamma##(x-ut)##
Under what circumstances is t=0?
Ah, I see. The thing is, I can use the full Lorentz transformation eqns in certain situations - but I don't understand when the Lorentz transforms reduce down to the 'shortcut' formulae I posted earlier.
i.e. in x'=\gamma(x-ut)
In what situation is x = 0?
I can understand the situation...
I am a little confused about the Galilean transforms.
If I have t'=\gammat
Is t ALWAYS the frame of reference that we are in?
i.e. If a spacecraft is moving away from Earth, and I wanted to measure the time taken on the spacecraft to reach some distance, would t be the variable I...
While investigating Coulomb's Law, I created a graph of F-1/2 vs. r to display results.
The gradient of this graph is much steeper than it should be. What factors could affect the electrostatic force to make this happen?
Any suggestions would be greatly appreciated!
(The experiment...