Recent content by Enochfoul

Im happy to show the solution for 3bi if you would like

D=Vout/Vin. There are 2 knowns in the question Duty Cycle which is 30% and Vout which is 7.5V. So Vout is 30% of Vin.

The problem stated had missing info. The Vout should have been 7.5V. Sorted it now thanks the lecturer missed it off by accident

Hi The missing piece has been found Vout= 7.5V Using the formula: Vout=Vref*(R1+R2/R2) Vout=1.25(10+2/2) = 7.5 R2 must be 2 does that look right?

Its an assignment question which I believe they have messed up on by omitting information.

I should have said 3b can't be solved

Homework Statement I came across this question in another forum and the members of the group said it can't be solved due to lack of information. Can anyone solve it? Homework EquationsThe Attempt at a Solution

After reading the spec sheet it referred to the current from the Adj pin as negligible and that it normally can be ignored. I am wondering something though, the spec sheet has a dropout min and max listed. It states the minimum is 1.3V. With this in mind would my calculation of 1.25V be an issue...

Hi thanks for your patience so far which will probably run out after this: Min Voltage V=IR 3.125*400=1.25V Max Voltage V=IR 3.175*5000=15.875V

I know if I just have to account for the 1.25v I would use the following formulas to get the range but where would the 50uF figure fit into the equation? VOUT=1.25∗(1+0/400) VOUT=1.25∗(1+5000/400)

1.25*(1+5000/400)=16.87V

I've had a go at a solution how does this look? Current through R2 =1.25/5000= 0.25mA Current through R1 =1.25/400= 3.12mA Then do I need to +50μA to R1 or R2 as well?

Vout = vref(1+R2/R1)

I messed up with the LaTeX there I apologise. Am I to ignore the vref of 1.25V in this circuit or does it have influence on the circuit? Thanks

Homework Statement [FONT=Thread-000016e0-Id-00000031] [/B] Calculate the output voltage range for the adjustable voltage regulator circuit shown in FIGURE 1. I have read an older post and have understood how the formula works but I am thrown off by the inclusion of the 50uA current coming...