Recent content by Enthusiast94

It's not about the drawing, it's about sending a message. : ) Anyway, thanks for your help.

What went wrong in the last diagram? Please be a bit more specific... As you said, I'll need two right triangles, so I drew a perp from the point at which it strikes to the opposite ray.

How about this? But, now the other two angles wouldn't be alpha/beta. :/

Could the given equation be derived w/o considering it as a right triangle? If so, please explain.

Using the new diagram(attached), I've got r1 = dcos(alpha) and r2 = dsin(beta). So now, delta r = r1 - r2 = d(cos alpha - cos beta). Does this make sense?

Homework Statement A narrow parallel light beam of wavelength 632.8 nm is incident upon a diffraction ruler (i.e. the light reflects off of the grating rather than passing through it). The ruler has 600 lines per mm. Show that the expression for the condition for constructive interference is...