Recent content by eo1989

Okay, I plugged the numbers in and sure enough it was .88. Thank you very much for helping me with this problem. I'll review this problem because I m sure it will be on my test Tuesday.Once again, thank you.

After distributing I got: .0675 V2f^2 - .3802 V2f + .5355 The original equation was: .2470 = .03((-1.5V2f) + 4.225)^2 + .045(V2f)^2 I added .045 V2f^2 to .0675 V2f^2 and then subtracted .2470 from .5355 and got: .1075 V2f^2 - .3802 V2f + .2885 Using the quadratic...

this is what I have so far:0 = 6.75(V1f)^2 + 53.55 + .045(V2f)^2 - .2470 Not to be so negative...but I think I did something wrong

Oh, I see. So would I just leave the equation as is? .2470 = .03((-1.5V2f) + 4.225)^2 + .045(V2f)^2 How do I go about answering when V2f is in there twice? Would I have to subtract one of them like so... .2470 - .045(V2f)^2 = .03((-1.5V2f) + 4.225)^2 Sorry for all the questions I'm just...

.2470 = .03((-1.5V2f) + 4.225)^2 + .045(V2f)^2 Do I distribute the .03 and .045, or am I missing something?

.2470 = 1/2(.06)[-(1.5)(V2f) + 4.225]^2 + 1/2(.09)(v2f)^2 .2470 = .03(-(1.5)(V2f) + 4.225)^2 + .045(V2f)^2 .2470 = .03((-1.5V2f) + 4.225)^2 + (.045V2f)^2 Is this right so far?

1/2(.06kg)(2.5m/s)^2 + 1/2(.09kg)(1.15m/s)^2 = 1/2(.06kg)[(-1.5)(V2f) +4.225)^2 + 1/2(.09kg)(V2f)^2 .25 = 1/2(.06kg)[(1.5)(V2f) + 4.225]^2 + 1/2(.09kg)(v2f)^2 ...would this be right?

i got this: V1f = - 1.5 (V2f) + 4.225 ...but, how do i plug this into the second equation?

is this right... -.06(V1f) = .09 (V2f) - .2535

can you please just get me going in the right direction i can't figure out how to solve it because of the two unknowns

when you say to solve the first equation for V1f do you mean: (.06kg)(2.5m/s) + (.09kg)(1.15m/s) = (.06kg)(V1f) + (.09kg)(V2f) .2535 = (.06kg)(V1f) + (.09kg)(V2f) .06kg(V1f) = .2535 + .09kg(V2f) .06kg/.06(V1f) = .2535/.06 + .09kg/.06(V2f) V1f = 4225 + 1.5 V2f

Yo zoobyshoe I'm really happy for you and ima let you finish, but Woodrow Wilson was the best Nobel Prize winners of all time. Was the pole vault accidentally discovered by a clumsy javelin thrower?

Homework Statement a .060kg tennis ball, moving with a speed of 2.5 m/s, collides head-on with a .09kg ball initially moving away from it at a speed of 1.15m/s. Assuming a perfect collision, what are the speed and direction of each ball after the collision Homework Equations MaVa +...