Recent content by erix335

took the derivative of the speed and hypotenuse equation...or so I thought, then filled in for T and put it under the distance (25)

2s(ds/dt)= (25-3t)^2 + ?(18-6t)^2 2(30.8 hyp of triangle) = 2(25-3t)3+2*18-6t)6 61.4=(50-6t)3+(36-12t)6 =366-90t -304.6/-90=t t=304.6/90 or 3.38...which seems to be a right answer but the second part of my equation had no real thought behind it. I seem to be stuck in the initial...

Homework Statement A man 6 feet tall walks away from a streetlight that is 18 feet tall. If the length of his shadow is changing at a rate of 3 feet per second when he is 25 feet away from the base of the light, how fast is he walking away from the light at this moment? Homework Equations...