Okay area under graph is 93.75 J
I use
93.75J = 0.5*0.5kg*v^2
→v =19.365m/s
Okay now I am sure it is correct!
Haha thanks for helping an idiot like me..I make so many simple mistakes with units..I'll keep that in mind for the future.thanks again
O
Ohhhhh... I understand...
Area under graph is 9375N of course and then
9375N : 500g=18.75 m/s
Thanks a lot, now I get a bonus to my grade :)
Just one last (stupid)question. Why isn't it possible to calculate the 18.75m/s using W=0.5*m*v^2 to calculate the velocity?
So the work is: 2.5cm*5000N =12500J
So then the work energy theorem says:
W=KEf-KE0
We can eliminate KE0 so it is
W=0.5*m*v^2
√(W/0.5*m)=v
So we get v=7.071m/s
This looks correct to me, but apparantely it is 19.0m/s
1. We know that we need 5000N to drive a nail 2.5 cm into a wall. How fast does a hammer of 500g mass have to be in order to drive the nail in the wall in one stroke?(look at the picture if it is unclear. The 2 cm in the picture should be 2.5cm)
2.
F=m*a
W=F*x
x=distance
3. I thought it...