sorry, yes, you're completely right, i must have made a mistake. Ok so is this logic ok?
2S2 ≥ 3 + S1(4-S1)
Well we already know that S1≥3 and S2 ≥ 3
So 2S2 ≥ 6
On the other hand, if we wish to maximise the right hand side of the equation, we want S1 to be its minimum, 3, hence the maximum...