Recent content by Evari5te

Thanks PhDeezNutz. There is a key difference in your initial integral to mine which is the ##\frac{1}{3}## multiplier. This entirely accounts for the mistake in my attempt, at it remains a constant multiplier along with the ##a^3## throughout and outside of the work resolving the integral...

The closest I can get is ##k=\frac{\sqrt{2}a}{\sqrt{3}}## as follows: ##I=\int_0^\pi y^2dA## ##\therefore I = \int_0^\pi a^2 \sin^2 x dA## ##dA = y.dx = a \sin x dx## ##\therefore I = \int_0^\pi a^3 \sin^3 x dx = a^3 \int_0^\pi \sin^2 x.\sin x dx## Let ##u=\sin^2x##, ##\therefore...

I'm seeking some reassurance I've understood the question since there are no answers given in the book and I'm getting a bit tied up in knots. What I am struggling with most is there are three per unit values for impedance already noted on the diagram without qualifying what ##Z{base}## is or...

Finally had a bit of time to circle back to this problem and indeed I had gone some way adrift. Thanks to TSny both for the steer and for using LaTex, which once I learnt to use it helped me with setting out my workings much more clearly and spotting the mistakes. Also for the common sense...

NOx is a generic problem with all Internal Combustion engines, including Diesel, Gasoline (Petrol to me) and synthetic fuels - hydrocarbons where the carbon is derived from the atmosphere rather than fossil. This sums it up quite well...

My apologies - took a while to remember where I had read it but here it is. https://www.cummins.com/news/2022/01/27/hydrogen-internal-combustion-engines-and-hydrogen-fuel-cells Paragraph after the infographic reads: "Hydrogen engines release near zero, trace amounts of CO2 (from ambient air...

I read somewhere that Hydrogen ICE's still produce oxides of nitrogen, which are deleterious to respiratory health. If we need to re-tool our transport to low or zero carbon, perhaps we should be moving away from combustion altogether to eliminate as many of the other pollutants that are...

Many thanks for the steer. I had a go at resolving this by setting |Ic open| = |Ic closed|, where |Ic| = sqrt( real terms^2 + imag. imag^2). In the end I ran into something of a cul-de-sac where my expression for R was a quadratic with complex roots, so I must have gone awry somewhere. I'll...

In = Ia + Ib + Ic from the above equations this is the mesh current I3. By my reckoning this is a current phasor as follows: I3 = ωC(√3 - 2/√3) + j/(√3R) Further simplifies to: ωC/√3 [ (3-2) + j/R ] = [ωC/√3] [ 1 + j/R]

My thoughts were I could use mesh current analysis to derive equations for current hence power in each case in terms of ωC and R, set the equations for real power equal to each other and solve for R. While ωC are known I opted to leave them as letters thinking this might make life easier when...

Hi everyone, I am a energy professional looking to expand my understanding of electrical power system design engineering, this in view of the large amount of electrification and distributed power generation projects I expect (will need) to happen in the coming years as part of net zero strategy.