Recent content by fellowsk

Alright, thanks. I'm so used to integrating from high school calculus, so now that we are not supposed to know how in my calc 125 class, I'm not really sure what I'm doing anymore. But I've worked it out by splitting the triangle in half, keeping the angle of 2pi/n, and I figured out how it works.

A)Let An be the area of a polygon with n equal sides inscribed in a circle with radius r. By dividing the polygon into n congruent triangles with central angle 2pi/n, show that An=(1/2)nr^2sin(2pi/n). B)Show that the limit as n approaches infinity = pir^2. Now, for part A, I don't understand...

See, I keep thinking that you would not be able to see the top half of the image. But the light rays from the top half of the object could strike the bottom part of the convex lens and still form the image. The same reasoning goes for covering the lens with a mask with a hole in it. Or would you...

I don't have the equipment to test it and experiment.

Ok, a lens is held upright with a piece of clay. In front of it is a bulb, and behind it is a screen at the location of the image of the bulb. Now, what would happen to the image if the top half of the lens were covered by a mask? And what if the mask had a small hole in the center and were...